PLEASE HELP ASSAAAAPPP

Answer:
[tex]\large\boxed{D.\ \dfrac{1}{16}}[/tex]
Step-by-step explanation:
[tex]4=2^2\\\\y=4\cdot2^x=2^2\cdot2^x\qquad\text{use}\ a^na^m=a^{n+m}\\\\y=2^{2+x}\\\\for\ x=-6\\\\y=2^{2+(-6)}=2^{2-6}=2^{-4}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\y=\dfrac{1}{2^4}=\dfrac{1}{16}[/tex]