Respuesta :
For this case we have the following equation:
[tex]y = 3cosx-1 [/tex]
We must find the maximum and minimum values of the equation to find the range.
We have then:
For x = 0
[tex]y = 3cos (0) -1 y = 3 (1) -1 y = 3-1 y = 2[/tex]
For x = pi
[tex]y = 3cos ( \pi ) -1 y = 3 (-1) -1 y = -3-1 y = -4[/tex]
The range of the function is given by:
[-4, 2]
Equivalently,
-4 ≤ x ≤ 2
Answer:
b) -4 ≤ x ≤ 2
[tex]y = 3cosx-1 [/tex]
We must find the maximum and minimum values of the equation to find the range.
We have then:
For x = 0
[tex]y = 3cos (0) -1 y = 3 (1) -1 y = 3-1 y = 2[/tex]
For x = pi
[tex]y = 3cos ( \pi ) -1 y = 3 (-1) -1 y = -3-1 y = -4[/tex]
The range of the function is given by:
[-4, 2]
Equivalently,
-4 ≤ x ≤ 2
Answer:
b) -4 ≤ x ≤ 2
Answer: The correct option is (b) [tex]-4\leq y\leq 2.[/tex]
Step-by-step explanation: We are given to select the correct range of the following function
[tex]y=3\cos x-1.[/tex]
We know that the range of the cosine function is from - 1 to 1.
That is,
[tex]-1\leq \cos x\leq 1\\\\\Rightarrow -(1)\times 3\leq 3\times \cos x\leq 3\times 1\\\\\Rightarrow -3\leq 3\cos x\leq 3\\\\\Rightarrow -3-1\leq 3\cos x-1\leq 3-1\\\\\Rightarrow -4\leq 3\cos x-1\leq 2\\\\\Rightarrow -4\leq y\leq 2.[/tex]
Thus, the range of the given function is [tex]-4\leq y\leq 2.[/tex]
Option (b) is CORRECT.
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