Question

r^2+7r+10/3 / 3-30/r2-5r-50

Answer 1

Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50 
=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) 
=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) 
=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) 
=(r+2)(r+10)/(r-10)

Answer 2

Answer:

umm i think its r+2

Step-by-step explanation:

((r²+7r+10)/3) × (3r-30)/(r²-5r=50)= Factoring the expression (r²+7r+10) we get  (r+2)(r+5)

Then multiply it with the other numerator, we get = (r+2)(r+5)(3(r-10)

Then we factorise = (r²-5r-50) = (r+5)(r-10)

Multiplying it with the other denominator, we have; = 3(r+5)(r-10)

Therefore dividing (r+2)(r+5)(3(r-10)/(3(r+5)(r-10) we get; = r+2

Therefore, the correct answer is r+2 (NOT MY WORK) (YAY)