Question

Solve −2x2 +3x − 9 = 0. (2 points)
Select one:
a. x equals quantity of 3 plus or minus 3i square root of 7 all over 4
b. x equals quantity of 3 plus or minus 9i square root of 7 all over 4
c. x equals quantity of negative 3 plus or minus 3i square root of 7 all over 4
d. x equals quantity of negative 3 plus or minus 9i square root of 7 all over 4

Answer 1

Answer:

Option A

Step-by-step explanation:

We have to find the solution of $-2x^{2}+3x-9=0$

By quadratic formula

$x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

$=\frac{-3\pm \sqrt{(3)^{2}-4(-2)(-9)}}{2(-2)}$

$=\frac{-3\pm \sqrt{9-72}}{-4}$

$=\frac{3\mp \sqrt{-63}}{4}$

$\frac{3\mp 3\sqrt{-7}}{4}=[\frac{3\mp 3i\sqrt{7}}{4}]$

Option A is the answer.

Answer 2

Answer:

Option A) x equals quantity of 3 plus or minus 3i square root of 7 all over 4.

Step-by-step explanation:

We are given the quadratic equation:

$-2x^2 +3x - 9 = 0$

To find the solution to this quadratic equation, we use the quadratic formula:

$ax^2 + bx + c = 0\\\\x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\\text{where a is the coefficient of } x^2\text{, b is the coefficient of x and c is the constnt term of the eqution.}$

Putting the value of a, b and c in the quadratic formula:

$a = -2\\b = 3\\c = -9\\\\x = \displaystyle\frac{-3 \pm \sqrt{3^2 - 4(-2)(-9)}}{2(-2)}\\\\x = \frac{-3 \pm \sqrt{-63} }{-4}\\\\x = \frac{-3 \pm 3i\sqrt7}{-4}\\\\x = \frac{3 \mp3i\sqrt7}{4}$

Hence, the correct option is option A) x equals quantity of 3 plus or minus 3i square root of 7 all over 4.