Question

When using the inspection method to rewrite the rational expression , what constant term must the numerator have for to be one of its factors? What number must you add to (and subtract from) the numerator's constant term to derive as a factor?
For the numerator to have as a factor, its constant term must be . To get this number, add and subtract from the numerator’s constant term.

Answer 1

What are the choices

Answer 2

If ( x + 6 ) is a factor, then putting x = - 6 should make f ( x ) = 0:
x² + 8 x + c
( - 6 )² + 8 * ( - 6 ) + c = 0
36 - 48 + c = 0
-12 + c = 0
c = 12

So the answer would be 12. I had this question.