Respuesta :
For this case, what we can do is use the Pythagorean theorem to find the magnitude of the displacement of the car.
We have then
[tex] d ^ 2 = 16 ^ 2 + 12 ^ 2 [/tex]
From here, we clear the value of d.
We have then:
[tex] d = \sqrt{16 ^ 2 + 12 ^ 2} [/tex]
Rewriting:
[tex] d = \sqrt{256 + 144} [/tex]
[tex] d = \sqrt{400} [/tex]
[tex] d = 20 miles [/tex]
Answer:
The magnitude of the car's displacement is:
d = 20 miles
We have then
[tex] d ^ 2 = 16 ^ 2 + 12 ^ 2 [/tex]
From here, we clear the value of d.
We have then:
[tex] d = \sqrt{16 ^ 2 + 12 ^ 2} [/tex]
Rewriting:
[tex] d = \sqrt{256 + 144} [/tex]
[tex] d = \sqrt{400} [/tex]
[tex] d = 20 miles [/tex]
Answer:
The magnitude of the car's displacement is:
d = 20 miles