Question

If the equation y = 1/6(x + 12) were graphed in the xy-plane, which of the following statements would be true of the graphed line?

A. It would be perpendicular to the graph of y = 1/6x + 3.

B. It would be parallel to the graph of 12y = 2x + 3.

C. It would have the same slope as the graph of x + 6y = 18.

D. It would have the same y‑intercept as the graph of y = 1/6x + 12.

Answer 1

Hi!

The answer B. It would be parallel to the graph of 12y = 2x + 3 is true because the slope of both 12y = 2x + 3 and y=$\frac{1}{6}$(x + 12) is $\frac{1}{6}$ which means that they run the same direction on a graph and the y-interscept for 12y = 2x + 3 is (0,$\frac{1}{4}$) and the y-interscept for y=$\frac{1}{6}$(x + 12) is (0,2). See graph below: