Question

The three sides of a triangular lot are represented by x, 2x, and 3x + 2. find each side if the perimeter of the triangular lot is 362 feet. the shortest side is . the middle side is . the longest side is .

Answer 1

x + 2x + (3x+2) = 362
6x = 360
x = 60
The triangle sides are 60, 120 and 182 feet

Answer 2

Answer:

Sides of triangle are, x , 2 x and 3 x +2 feet Respectively.

Perimeter = 362 feet

Perimeter of any triangle= Sum of the length of three sides

 →  362 = x + 2 x + 3x +2

→6 x +2=362

→6 x= 362-2

→6 x=360

Dividing both side by ,6 we get

$x=\frac{360}{6}\\\\x=60$

One side of triangle=60 feet→→shortest side

Second side  =2 x=2×60=120 feet→→ middle side

Third side =3 x + 2=3×60+2=180+2=182 feet→→ longest side