The answer is: " 40 % " .
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Note:
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If "3/5" of the students ride the bus, then "2/5" do not ride the bus".
Since: "3/5" + "2/5" = "(3 + 2)" / 5 = 5/5 = "1" (as in "1 whole").
1 – (3/5) = (5/5) – (3/5) = (5 – 3) / 5 = 2/5.
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Now, express: "2/5" as a percentage ;
→ "2/5" = "x / 100 " ; Solve for "x"
Cross-multiply: Note:
→ Given: "[tex] \frac{a}{b}[/tex]" = "[tex] \frac{c}{d}[/tex]" ;
→ " bc = ad" ; {" b[tex] \neq [/tex]0 ; d[tex] \neq [/tex]0 "} .
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As such:
→ "[tex] \frac{2}{5}[/tex]" = "[tex] \frac{x}{100}[/tex]" ;
→ " 5x = (2)*(100) " ; → Solve for "x" ;
→ " 5x = 200 " ;
→ Divide each side of the equation by "5" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ " 5x / 5 = 200 / 5 " ;
to get:
→ " x = 40 " ;
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So; we have:
→ "2/5" = "40 / 100 " ;
→ "2/5" = " 40 % " .
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The answer is: " 40 % " .
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