Answer: [tex]3.9\times 10^{23}[/tex] molecules of [tex]Cu(NO_3)_2[/tex]
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]\text{Number of moles of} Cu(NO_3)_2=\frac{122g}{187.56 g/mol}=0.65[/tex]
1 mole of [tex]Cu(NO_3)_2[/tex] contains=[tex]6.022\times 10^{23}[/tex] molecules of [tex]Cu(NO_3)_2[/tex]
Thus 0.65 moles of [tex]Cu(NO_3)_2[/tex] contains=[tex]\frac{6.022\times 10^{23}}{1}\times 0.65=3.9\times 10^{23}[/tex] molecules of [tex]Cu(NO_3)_2[/tex]
Thus there are [tex]3.9\times 10^{23}[/tex] molecules of [tex]Cu(NO_3)_2[/tex]