Question

x y
2 5
4 10
6 15
8 20


Object A and Object B are two objects in motion. Given the table of Object A and the equation y =
18
5
x of Object B, which of the two moving objects has greater speed and by what factor? (round to nearest hundredth)
A) Object A by a factor of 1.10
B) Object B by a factor of 1.10
C) Object A by a factor of 1.44
D) Object B by a factor of 1.44

Answer 1

The Answer is D:Object B by a factor of 1.44

Object A: 5/2 = 2.5
Object B: 18/5 = 3.6

That being so
3.6/2.5 = 1.44

You're Welcome.

Answer 2

Answer:

D) Object B is faster by a factor of 1.44

Step-by-step explanation:

Using the table for Object A, we will find the equation representing its motion.

Since, slope = $\frac{10-5}{4-2}=\frac{5}{2}$

So, substituting the slope and (2,5) in the equation 'y=mx+b', where m= slope, we get,

$5=\frac{5}{2}\times 2+b$ i.e. b = 0

So, the equation for the motion of Object A is, $y=\frac{5}{2}x$

Also, the equation for the motion of Object B is, $y=\frac{18}{5}x$

That is,

Speed of Object A = $\frac{5}{2}=2.5$

Speed of Object B = $\frac{18}{5}=3.6$

So, the factor of increase in the speed = $\frac{3.6}{2.5}$ = 1.44

Hence, Object B is faster by a factor of 1.44.

Thus, option D is correct.