Answer:
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The area of the circular mirror, in "square inches", is:
is: " 254.34 in² " .______________________________________________________
Note:
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diameter, "d" = 18 in. (given) ;
radius, "r" = "d/ 2 " = "(18 inches) / 2 " = 9 in. ;
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Area of a circle, "A" :
A = [tex] \pi [/tex] * r² ;
in which: " A = Area of circle ("plate"); in units of "square inches"; or "in² " ;
" [tex] \pi [/tex] = 3.14 " {approximation we shall use} ;
"r = radius = 9 in." ;
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Plug in our known values to solve for the area, "A" :
A = (3.14) * (9 in)² ;
A = (3.14) * (9)² * (in²) ; A = (3.14) * (9) * (9) * (in²) ;
A = (3.14) * (81) * (in²) ;
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A = 254.34 in² .
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