Respuesta :
what we Know: 3 box have some counters. There are 63 counters when they are all combined.
A and B counters = 36
The difference between A and C is 10.
Since we already know A and B we can subtract them from 63 to get C
C= 63- 36 = 27
Now we have to find A by looking for what number gives us the difference of 10 when subtracted from C.
36 = 18+ 18 or 19+ 17
18 and 18 wont work because it does not give us the difference of 10.
So A = 17 counters and B = 19 counters.
A and B counters = 36
The difference between A and C is 10.
Since we already know A and B we can subtract them from 63 to get C
C= 63- 36 = 27
Now we have to find A by looking for what number gives us the difference of 10 when subtracted from C.
36 = 18+ 18 or 19+ 17
18 and 18 wont work because it does not give us the difference of 10.
So A = 17 counters and B = 19 counters.
The number of counters in the each of the three boxes is required.
The counters in box A is 17 box B is 19 and box C is 27.
Let number of counters in box A be [tex]x[/tex]
Number of counters in box B be [tex]y[/tex]
Number of counters in box C be [tex]z[/tex]
[tex]x+y+z=63[/tex]
[tex]x+y=36\\\Rightarrow y=36-x[/tex]
[tex]z-x=10\\\Rightarrow z=10+x[/tex]
[tex]x+36-x+x+10=63\\\Rightarrow x+46=63\\\Rightarrow x=17[/tex]
[tex]y=36-x=36-17=19[/tex]
[tex]z=10+x=10+17=27[/tex]
The counters in box A is 17 box B is 19 and box C is 27.
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