Respuesta :

ANSWER

[tex]( \frac{f}{g} )(x) = \frac{4x + 1}{ {x}^{2} - 5 } .[/tex]
where,

[tex]x\ne \pm \sqrt{5} [/tex]


EXPLANATION

We were given that

[tex]f(x) = 4x + 1[/tex]
and
[tex]g(x) = {x}^{2} - 5[/tex]


We are supposed to find
[tex]( \frac{f}{g} )(x)[/tex]


Recall that,

[tex]( \frac{f}{g} )(x) = \frac{f(x)}{g(x)} [/tex]
We substitute the functions to obtain,

[tex]( \frac{f}{g} )(x) = \frac{4x + 1}{ {x}^{2} - 5 } [/tex]


This is a proper rational function and it is in the simplest form.


The restriction is that,

[tex]x\ne \pm \sqrt{5} [/tex]

If the denominator is zero the function will be undefined

A function assigns the values. The value of  (f/g)(x) is (4x+1)/(x²-5).

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Given the function f(x)=4x+1 and the function g(x)=x²-5, therefore, the value of (f/g)(x) will be,

(f/g)(x) = f(x)/g(x)

           = (4x+1)/(x²-5)

Hence, the value of  (f/g)(x) is (4x+1)/(x²-5).

Learn more about Function:

https://brainly.com/question/5245372

#SPJ5

ACCESS MORE