Well the area of a trapezoid is defined by the following formula:
A = [tex] \frac{1}{2}(b_{1} + b_{2})h [/tex] where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.
Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A = [tex] \frac{1}{2} (15+25)(7)=140[/tex]
This is in square units of measure of course, so 140 in²
