Respuesta :
According to Hasselbalch equation pH = pKa at the equal point. When pH equals the pKa value of the indicator, the base and acid forms of indicator are present in the ratio of 1:1
(9.3 + 10.5) / 2 =9.9
pKa = 9.9
Using the equation pH = pKa at equal point we get
Ka = 10^- pKa
Ka = 10^- 9.9
Ka = 1.26 x 10^-10
Ka = 1 x 10^-10
(9.3 + 10.5) / 2 =9.9
pKa = 9.9
Using the equation pH = pKa at equal point we get
Ka = 10^- pKa
Ka = 10^- 9.9
Ka = 1.26 x 10^-10
Ka = 1 x 10^-10
The Ka of thymolphthalein is mathematically given as
Ka = 1 x 10^{-10 }
What is Ka of thymolphthalein?
Question Parameters:
an indicator that changes color over a range from pH=9.3 to pH=10.5.
Generally, the pKa of thymolphthalein is mathematically given as
Pka=(9.3 + 10.5) / 2
Pka=9.9
Therefore
pH = pKa
Ka = 10^- pKa
Ka = 1.26 x 10^-10}
Ka = 1 x 10^{-10 }
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