Question

Using the technique in the model above, find the missing segments in this 30°-60°-90° right triangle.



AD = 6
DB = 2
AC =

Answer 1

For this case what you should do is use the following trigonometric relationship:
 $cos (x) = \frac{C.A}{h}$
 Where
 x: angle
 C.O: adjoining cathetus
 h: hypotenuse
 Substituting the values we have:
 $cos (x) = \frac{AD}{AC}$
 $cos (30) = \frac{6}{AC}$
 $AC = \frac{6}{cos30}$
 $AC = 6.93$
 Answer: 
 $AC = 6.93$

Answer 2

Answer:

4√3

Step-by-step explanation:

Add line AD and line DB together to get 8. Now we know that the length of the hypotenuse is 8.  We can then figure out what the long side of the triangle is (line AC), by dividing the hypotenuse by 2, and multiplying by the square root of 3.

Line AC is then 8/2 x √3 = 4√3

I hope this makes sense, and I just did this assignment and got full marks. Let me know if I can explain any other problems from this assignment or if I should make my answer clearer. : )