Question

incorrect, 4.3.37

In how many ways can a committee of four

men and three

women be formed from a group of ten

men and six

​women?

Answer 1

The number of ways is given directly using the formula:
$C_{10}^4\times C_6^3\\\text{wherein }C_n^k=\dfrac{n!}{k!(n-k)!}.\text{ Using the formula we get:}\\C_{10}^4\times C_6^3=\dfrac{10!}{4!(10-4)!}\dfrac{6!}{3!(6-3)!}\\=4200$
(Use a calculator in order to reach the above result.)
So tête number of ways is 4200.

Answer 2

2 with a remainder of one man