A company says that the probability of finding an all-star card in a game pack is 12.5%. A student wants to determine the probability that, if he buys 6 game packs, 2 or more will have an all-star card. To do this, he uses a random number table to pick 6 numbers from 1 to 8. He lets 1 represent a pack with an all-star card and 2 through 8 represent a pack without an all-star card. He repeats this for a total of 15 trials. The results are shown in the table. 561673 366468 314255 361362 838443 126285 257231 768551 652585 468113 123711 322764 487626 783134 384664 Select from the drop-down menus to correctly complete each statement. To estimate the probability that 2 or more out of 6 packs will have an all-star card, the student must count the number of trials with and divide by the number of trials. This gives an estimated probability of about . 20 pts for the first one to answer and if it is correct you get brainiest answer

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Answer:

The estimated probability is about:

0.1333=13.33%

Step-by-step explanation:

It is given that:

The probability of finding an all-star card in a game pack is 12.5%.

A student wants to determine the probability that, if he buys 6 game packs, 2 or more will have an all-star card.

He uses a random number table to pick 6 numbers from 1 to 8.

He lets 1 represent a pack with an all-star card and 2 through 8 represent a pack without an all-star card.

The results of 15 trials are given as:

561673   366468    314255    361362    838443   126285    257231   768551    652585    468113    123711    322764    487626    783134    384664

So, the number of trials that have two or more 1 in it will represent the trial that 2 or more out of 6 packs will have an all-star card.

Number of trials that represent that 2 or more out of 6 packs have an all-star are:2

( Since, the trials are: 468113 and   123711 )

Hence, the estimated  probability that 2 or more out of 6 have an all-star is:

2/15=0.13333=13.33%

Answer:

2 or more 1s and .13

Explanation:

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