Respuesta :
The dimensions of the actual image are 8 inches long by 11 inches wide.
The new scale gives a drawing that is 32 cm long by 44 cm wide.
We use proportions to solve this. For the length of the actual image:
6/1 = 48/x
Cross multiply:
6*x = 48*1
6x = 48
Divide both sides by 6:
6x/6 = 48/6
x =8 inches
For the width of the actual image:
6/1 = 66/x
6*x = 66*1
6x = 66
Divide both sides by 6:
6x/6 = 66/6
x = 11
For the new scale image, use the new scale:
Length:
4/1 = x/8
Cross multiply:
4*8 = x*1
32 = x
Width:
4/1 = x/11
4*11 = x*1
44 = x
The new scale gives a drawing that is 32 cm long by 44 cm wide.
We use proportions to solve this. For the length of the actual image:
6/1 = 48/x
Cross multiply:
6*x = 48*1
6x = 48
Divide both sides by 6:
6x/6 = 48/6
x =8 inches
For the width of the actual image:
6/1 = 66/x
6*x = 66*1
6x = 66
Divide both sides by 6:
6x/6 = 66/6
x = 11
For the new scale image, use the new scale:
Length:
4/1 = x/8
Cross multiply:
4*8 = x*1
32 = x
Width:
4/1 = x/11
4*11 = x*1
44 = x
Answer:
1). Length = 8 and width = 11 cm
2). Width = 44 cm
Step-by-step explanation:
A publisher scales up the front cover of the magazine using a scale of 6 cm to 1 inch.
Since the length and width of the scale drawing are 48 cm. and 66 cm.
By the scale factor we have to find the scaled length of the cover.
∵ 6 cm length of the cover = 1 inch
∴ 1 cm length of the cover = [tex]\frac{1}{6}[/tex] inch
∴ 48 cm length of the cover = [tex]\frac{48}{6}[/tex] inch
= 8 inches
Similarly scaled width of the cover = [tex]\frac{66}{6}[/tex] = 11 inches
Since width of the magazine cover was too big to view on computer.
So new scale 4 cm to inch was used.
By this scale factor we have to find the scaled width of the drawing.
∵ 1 inch width of the drawing = 4 cm
∴ 11 inch width of the drawing = 11×4
= 44 cm.