Question

A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min how far does the car travel while it is accelerating

Answer 1

the acceleration is given by:
a=(v2-v1)/t
where
a=accelaration
v2=second velocity
v1=first velocity
thus the acceleration will be:
v1=6.5 m/s
v2=24 m/s
t=3.5min=210 sec

thus
a=(24-6.5)/210
a=0.09286 m/s²

Answer: 0.09286 m/s²

Answer 2

Answer:

Distance traveled by car during acceleration = 3203.78 m

Step-by-step explanation:

We have equation of motion v = u + at

    Final velocity, v = 24 m/s

    Initial velocity, u = 6.5 m/s

    Time, t = 3.5 min = 210 s

Substituting

     v = u + at

     24 = 6.5 + a x 210

          a = 0.0833 m/s²

Now we have equation of motion, v² = u²+2as

Substituting

                     v² = u²+2as

                     24² = 6.5²+2 x 0.0833 x s

                     s = 3203.78 m

Distance traveled by car during acceleration = 3203.78 m