Respuesta :

check the picture below.

so, is really just a circle with a diameter of 8, inscribed in a square whose sides are 8 each.

since the diameter of the circle is 8, its radius is half that, or r = 4.

now, if we get the area of the square, namely 8*8, that includes the circle's area, but if we also get the area of the circle, namely A =πr² and thus π4² and "subtract" it, we're in effect making a hole in the square, and what's leftover is the shaded region.

[tex]\bf \stackrel{square's~area}{(8\cdot 8)}~~-~~\stackrel{circle's~area}{\pi 4^2}[/tex]
Ver imagen jdoe0001

Answer:

The correct option is 3.

Step-by-step explanation:

The given figure is a square and the a circle inscribed in it.

It is given that the length of side of square is 8 m. So the diameter of the circle is 8 m and radius is 4 m.

The area of a square is

[tex]A=a^2[/tex]

Substitute a=8 to find the area of square.

[tex]A_1=8^2=64[/tex]

The area of a circle is

[tex]A=\pi r^2[/tex]

Substitute π=3.14 and r=4.

[tex]A_2=(3.14)(4)^2=50.24[/tex]

The area of shaded region is the difference of area of square and circle.

[tex]A=A_1-A_2[/tex]

[tex]A=64-50.24[/tex]

[tex]A=13.76[/tex]

The area of shaded region is 13.76 m². Therefore the correct option is 3.

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