Question

Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?
(R = 0.08205 L atm/K mol)

Answer 1

pV = nRT

p = nRT/V 

p= 1 x 0.08205 x 1000/ 2

p = 41.025 Pa  

Edit: The unit should be atm instead of Pa, as pointed out by a nice human being.

Answer 2

PV = nRT
P = ???
V = 2 liters.
n = 1 mol
T = 1000 K
R = 0.08205

P = nRT/V
P = 1 * 0.08205 * 1000 / 2
P = 41.03 atmospheres. That's a pretty big pressure. <<<< answer.