To solve this exercise you must follow the proccedure below:
a) Find the maximum height of the tennis ball:
You have that the path of the ball can be represented by h=-16t²+18t+5. Then:
t=-b/2a
t=-18/2(-16)
t=0.562
h=-16t²+18t+5
h=-16(0.562)²+18(0.562)+5
h=10.06
b) How long will it take to reach the ground?
h=-16t²+18t+5
h=0
-16t²+18t+5=0
You must apply the quadratic equation:
t=(-b±√(b^2-4ac))/2a
a=-16
b=18
c=5
When you substitute the values, you obtain:
t=1.35