Question

What are the zeros of the quadratic function?

f(x)=2x^2−128

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and

Answer 1

6 and -6
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Answer 2

Answer:

$x={\pm}8$

Step-by-step explanation:

The given quadratic function is:

$f(x)=2x^2-128$

In order to find the zeros of the quadratic function, we put $f(x)=0$.

thus, we have

$f(x)=0$

⇒$2x^2-128=0$

⇒$2x^2=128$

⇒$x^2=64$

⇒$x={\pm}8$

Therefore, the values of x are 8 and -8.