Respuesta :
Answer:
Let amount of water in tank =y(100≤y≤500)
Amount of water drained in a day = c [2≤c≤5]
Time =x [1≤x≤ number of days till water in the tank drains out]
So Equation that models the relationship between time (x) and water volume (y) in slope-intercept form=
y = m x+ c,
If x=0, y=400 gallon,and if x=1 day then y=396
This is a linear graph.
[tex]\frac{y-400}{x-0}=\frac{400-396}{0-1}\\y-400=-4x\\y=-4x+400[/tex]
Amount of water in the tank after 2 days =
y=-4×2+400=-8+400=392
Here ,m = -[amount of water drained in a day]= -c= -4
[tex]y=-4x+400\\4x+y=400\\\frac{x}{100}+\frac{y}{400}=1[/tex]
x-intercept=100, y-intercept=400
Y intercept shows amount of water in the beginning.
As we can see that as time increases volume of water in the tank decreases.So linear equation of two variable completely or exactly satisfies the relationship between time and volume.
If we divide y intercept by x intercept i.e amount of water tank has by x intercept we get amount of water draining in a day.
Answer:
Step-by-step explanation:
Let amount of water in tank =y(100≤y≤500)
Amount of water drained in a day = c [2≤c≤5]
Time =x [1≤x≤ number of days till water in the tank drains out]
So Equation that models the relationship between time (x) and water volume (y) in slope-intercept form