Answer: 9.8 m/s2
The skydiver’s acceleration is equal to the acceleration due to gravity or 9.8 meters/seconds^2 since there is no forward velocity and the skydiver is just free falling. The equation would be Vf=Vi + a(t) where Vf is the final velocity, Vi is the initial velocity, a is acceleration due to gravity, and t is time.
With this, a skydiver's downward acceleration is like any falling object, which is about 28-35 feet per second squared and this will decrease over a few seconds and approaches zero as the skydiver reaches terminal velocity. Therefore, his Vf is equal to his Vi which is 0 and the instant jumps out from the helicopter is t=0 so his acceleration will be the acceleration due to gravity.
