Question

When 711 J of heat is added to a 41.1 g of an unknown metal, the temperature of the metal increases from 22oC to 94oC. Calculate the specific heat of this metal

Answer 1

the   specific  heat  capacity  of   the  metal  is   calculated  as follows

  heat energy =  Mc delta  T
heat  energy (Q) = (711 j  )
m=mass    (41.1 g)
c=  specific  heat  capacity  =?
delta  t =  change  in  temperature(  94 -22=72)

c=  Q/m  delta  T
  c=711 j  /  (41.1 g  x72)  =  0.240  j/g /k