Respuesta :
The correct answer is 0.11.
Explanation:
This is binomial, as there are a fixed number of trials, the probability of each trial is independent, and there are only two outcomes. Since that is the case, we will calculate:
[tex]_nC_r(p)^r(1-p)^{n-r}=_{50}C_{25}(0.5)^{25}(1-0.5)^{50-25} \\ \\=\frac{50!}{25!25!}(0.5^{25})(0.5^{25})=0.11[/tex]
Explanation:
This is binomial, as there are a fixed number of trials, the probability of each trial is independent, and there are only two outcomes. Since that is the case, we will calculate:
[tex]_nC_r(p)^r(1-p)^{n-r}=_{50}C_{25}(0.5)^{25}(1-0.5)^{50-25} \\ \\=\frac{50!}{25!25!}(0.5^{25})(0.5^{25})=0.11[/tex]
Answer: Probability of getting 25 heads is 0.11 or 11%.
Step-by-step explanation:
Since we have given that
A fair coin is tossed 50 times.
So, here, N = 50
Probability of getting a head = [tex]\dfrac{1}{2}[/tex]
Probability of getting a tail = [tex]\dfrac{1}{2}[/tex]
So, we will apply "Binomial distribution":
Let X is the number of getting heads.
[tex]P(X=25)=^{50}C_{25}p^{25}q^{25}[/tex]
Here, [tex]p=0.5,\ q=0.5[/tex]
So, it becomes,
[tex]P(X=25)=^{50}C_{25}(0.5)^{25}\times (0.5)^{25}\\\\P(X=25)=0.1122\\\\P(X=25)\approx 0.11[/tex]
Hence, Probability of getting 25 heads is 0.11 or 11%.