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20-03-2018
Mathematics

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Body temperatures are normally distributed with a mean of 98.6° f and a standard deviation of 0.19° f. what temperature represents the 95th percentile?

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hmaldonado90oqs9f3 hmaldonado90oqs9f3

20-03-2018

The 95th percentile of a standard normal distribution is 1.645
That is, P( z < 1.645) = .95

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