Respuesta :
The first thing we must do for this case is to find the surface area of the rectangular prism.
We have then:
A = 2 * (l * h) + 2 * (h * w) + 2 * (w * l)
Where,
w: width
l: long
h: height
Substituting values we have:
A = 2 * (10 * 8) + 2 * (8 * 8) + 2 * (8 * 10)
A = 448 in ^ 2
Answer:
the least amount of wrapping paper needed to wrap the gift box answer is:
A = 448 in ^ 2
We have then:
A = 2 * (l * h) + 2 * (h * w) + 2 * (w * l)
Where,
w: width
l: long
h: height
Substituting values we have:
A = 2 * (10 * 8) + 2 * (8 * 8) + 2 * (8 * 10)
A = 448 in ^ 2
Answer:
the least amount of wrapping paper needed to wrap the gift box answer is:
A = 448 in ^ 2
To find the least amount of wrapping paper needed, you will find the surface area of the rectangular prism.
These are the areas of all the faces.
Top/Bottom: 8 x 8 = 64 in.²
Front/Back. 8 x 10 = 80 in.²
Left Side/Right Side: 8 x 10 = 80 in.²
(64 x 2) + (80 x 2) + (80 x 2) =
448 in.²
The least amount of wrapping paper needed is 448 in.².
These are the areas of all the faces.
Top/Bottom: 8 x 8 = 64 in.²
Front/Back. 8 x 10 = 80 in.²
Left Side/Right Side: 8 x 10 = 80 in.²
(64 x 2) + (80 x 2) + (80 x 2) =
448 in.²
The least amount of wrapping paper needed is 448 in.².