Respuesta :
The dissociation of butanoic acid in water gives CH3CH2CH2COO^- and H+
This is according to the following equation
CH3CH2CH2COOH + H2O --->CH3CH2CH2COO^- + H^+
This is according to the following equation
CH3CH2CH2COOH + H2O --->CH3CH2CH2COO^- + H^+
Answer:
CH₃CH₂CH₂COOH → H⁺ + CH₃CH₂CH₂COO⁻
Explanation:
Butanoic acid is an organic acid that dissociates in water to release a proton.
CH₃CH₂CH₂COOH → H⁺ + CH₃CH₂CH₂COO⁻
Butanoic acid is also known as a carboxylic acid, where -COOH is the carboxylic group. The anion CH₃CH₂CH₂COO⁻ is known as butanoate.
H⁺ + H₂O → H₃O⁺
The proton released combines with water to form hydronium ion.