Question

For the reaction 2ch4(g)⇌c2h2(g)+3h2(g) k = 0.135 at 1615 ∘c . what is kp for the reaction at this temperature?

Answer 1

We can get Kp value from this formula:
Kp = Kc(RT)^Δn
when Kc= 0.135 
and R = 0.08206 L.atm/mol.K
and Δn = total number of moles of products - total number of moles of reactants
             = 1+3-2 = 2 
T= tempreature in kelvin = 1615 °C+273 =1888 K
so by substitution:

∴ Kp = 0.135 * (0.08206 * 1888)^2
         = 3240.4  

Answer 2

Kp is the equilibrium constant.The Kp value for the given reaction is 3240.4.

$\bold {2CH_4(g) \rightleftharpoons C_2H_2(g)+3H_2(g)}$

2 moles of methane form 1 mole of acetylene and one mole of Hydrogen.

Kp is the equilibrium constant. It is calculated from the partial pressures of a reaction equation. It express the relationship between product pressures and reactant pressures.

Formula of Kp,

$\bold {Kp = Kc(RT)^\Delta ^n}$

Where,

Kp - Equilibrium constant based on pressure

Kc - Equilibrium constant based on concentration = 0.135

R - gas constant  = 0.08206 L.atm/mol.K

$\bold {\Delta n}$ - moles of gaseous products = 1+3-2 = 2

T - temperature in kelvin = 1615 °C+273 = 1888 K

Put the values in the formula

$\bold {Kp = 0.135 \times (0.08206 \times 1888)^2}\\\\\bold {Kp = 3240.4 }$

The Kp value for the given reaction is 3240.4.

To know more about equilibrium constant,

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