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if black fur is dominant it would have to be B and the white fur is b. so if it is BB x bb you can use the punnet square and you would get all heterozygous offspring

The probability of producing a homzygous offspring in a cross between bb × bb is 100% or 1.

  • According to this question involving a gene coding for fur color in pigs, the allele for black fur (B) is dominant over the allele for white fur (b).

  • In a cross between bb × bb i.e. two homzygous (white furred) pigs, all of the offsprings will have a genotype bb.

  • Genotype bb means that all of the offsprings have a homzygous genotype and a white furred phenotype.

  • Therefore, probability of producing a homzygous offspring in a cross between bb × bb is 100% or 1 i.e. 4/4.

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