Respuesta :
The correct answer is: [C]: " 5√3 " .
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Explanation:
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In a "30-60-90" triangle:
The side opposite from the "30° angle" is "x" ;
The side opposite from the "60° angle is: "x√3" ;
and the "hypotenuse" is: "2x" ;
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So, from the "image attached":
The side opposite from the "60° angle is: "x√3" ; which equals: " 15 " (given) ;
So, x√3 = 15 ;
Divide each side by "√3" ; to isolate "x" on one side of the equation ;
& to solve for "x" ;
(x√3) / √3 = 15 / √3 ;
x = 15 / √3 ;
→ Multiply the entire equation by "√3/√3" (which equals "1"); to get ride oif the "square root" in the "denominator" ;
→ " 15 / √3 = (15 *√3) / (√3 * √3) " ;
= (15√3) / 3 ;
= 5√3 ; which is: Answer choice: [C]: " 5√3 " .
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_________________________________________________
Explanation:
_________________________________________________
In a "30-60-90" triangle:
The side opposite from the "30° angle" is "x" ;
The side opposite from the "60° angle is: "x√3" ;
and the "hypotenuse" is: "2x" ;
_________________________________________________
So, from the "image attached":
The side opposite from the "60° angle is: "x√3" ; which equals: " 15 " (given) ;
So, x√3 = 15 ;
Divide each side by "√3" ; to isolate "x" on one side of the equation ;
& to solve for "x" ;
(x√3) / √3 = 15 / √3 ;
x = 15 / √3 ;
→ Multiply the entire equation by "√3/√3" (which equals "1"); to get ride oif the "square root" in the "denominator" ;
→ " 15 / √3 = (15 *√3) / (√3 * √3) " ;
= (15√3) / 3 ;
= 5√3 ; which is: Answer choice: [C]: " 5√3 " .
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So, tan30 = x / 15;
Then, [tex] \frac{\sqrt{3}}{3} = \frac{x}{15} ;
x = \frac{15\sqrt{3}}{3};
x = 5\sqrt{3}.
[/tex]
The correct answer is : [tex] 5\sqrt{3} . [/tex]