Respuesta :

the correct answer is 5

Let us first define line of symmetry of parabola :

It is the line of symmetry of a parabola that divides a parabola into two equal halves that are reflections of each other about the line of symmetry. It intersects a parabola at its vertex. It is a vertical line with the equation of x = -b/2a.

So using the formula x=-b/2a, we can find the line of symmetry of parabola here.

We are given the equation:

[tex] x^{2} -10x+21 =0 [/tex]

If we compare it with the quadratic equation :

[tex] ax^{2} +bx+c=0 [/tex]

we get a=1, b=-10 and c=21

Now plugging the values of a and b in the formula x=-b/2a,

[tex] x= \frac{-b}{2a} [/tex]

[tex] x= \frac{-(-10)}{2(1)} [/tex]

x=5

So the line of symmetry of given parabola is given by x=5

Option D is correct answer.


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