Respuesta :
Let us first define line of symmetry of parabola :
It is the line of symmetry of a parabola that divides a parabola into two equal halves that are reflections of each other about the line of symmetry. It intersects a parabola at its vertex. It is a vertical line with the equation of x = -b/2a.
So using the formula x=-b/2a, we can find the line of symmetry of parabola here.
We are given the equation:
[tex] x^{2} -10x+21 =0 [/tex]
If we compare it with the quadratic equation :
[tex] ax^{2} +bx+c=0 [/tex]
we get a=1, b=-10 and c=21
Now plugging the values of a and b in the formula x=-b/2a,
[tex] x= \frac{-b}{2a} [/tex]
[tex] x= \frac{-(-10)}{2(1)} [/tex]
x=5
So the line of symmetry of given parabola is given by x=5
Option D is correct answer.