Quadrilateral BCDE is inscribed inside a circle as shown below. Write a proof showing that angles C and E are supplementary. Circle A is shown with an inscribed quadrilateral labeled BCDE.
![Quadrilateral BCDE is inscribed inside a circle as shown below Write a proof showing that angles C and E are supplementary Circle A is shown with an inscribed q class=](https://us-static.z-dn.net/files/dc1/ea0cd169244b5192d4f3ab7c9ba5463b.gif)
Answer:
The sum of angle C and E is 180°. So, C and E are supplementary angles.
Step-by-step explanation:
Given information: Quadrilateral BCDE is inscribed inside a circle.
To prove : angles C and E are supplementary, i.e., ∠C+∠E=180°.
Proof:
BCDE is a cyclic quadrilateral.
According to central angles theorem, the inscribed angle on a circle is half of its central angle.
By using Central angle theorem
[tex]\angle C=\frac{1}{2}\times arc (BED)[/tex]
[tex]2\angle C=arc (BED)[/tex] .... (1)
[tex]\angle E=\frac{1}{2}\times arc (BCD)[/tex]
[tex]2\angle E=arc (BCD)[/tex] ..... (2)
The complete central angles of a circle is 360°.
[tex]arc (BED)+arc (BCD)=360^{\circ}[/tex]
Using (1) and (2), we get
[tex]2\angle C+2\angle E=360^{\circ}[/tex]
[tex]2(\angle C+\angle E)=360^{\circ}[/tex]
Divide both sides by 2.
[tex]\angle C+\angle E=180^{\circ}[/tex]
The sum of angle C and E is 180°. So, C and E are supplementary angles.
Hence proved.