Question

To begin with Snape thinks we should review an ideal gas problem. What is the pressure exerted by 0.703 mol O2 in a 11.0 L container at 314 K. Express your answer in atmospheres.

Answer 1

The pressure exerted by 0.703 mol ${{\text{O}}_2}$ in a 11.0 L container at 314 K is $\boxed{{\text{1}}{\text{.647 atm}}}$.  

Further explanation:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept, and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is considered as the equation of state for any hypothetical gas. The expression for the ideal gas equation of gas is as follows:

${\text{PV}} = {\text{nRT}}$                ...... (1)

Here,

P is the pressure of the gas.

V is the volume of gas.

n denotes the number of moles of gas.

R is the gas constant.

T is the temperature of gas.

Rearrange the equation (1) to calculate P.

${\text{P}}=\dfrac{{{\text{nRT}}}}{{\text{V}}}$          ...... (2)

Given,

Volume of gas (V) is 11L.

Temperature of gas(T) is 314K.

Numbers of moles(n) are 0.703mol.

Universal gas constant R is $0.0821{\text{ atm}}\cdot{\text{L/mol}}\cdot{\text{K}}$ .

Substitute the values of V, T, R, n in equation (2) to calculate the pressure.

 $\begin{aligned}{\text{P}}&=\dfrac{{\left( {{\text{0}}{\text{.703 mol}}} \right)\times\left( {0.0821{\text{ atm}} \cdot {\text{L/mol}}\cdot {\text{K}}}\right)\times\left( {{\text{314 K}}}\right)}}{{{\text{11 L}}}}\\&= {\text{1}}{\text{.647 atm}}\\\end{aligned}$

The pressure exerted by ${{\mathbf{O}}_{\mathbf{2}}}$ gas is 1.647 atm.

Learn more:

1. What is the concentration of hydroxide ion of an unknown acid.

https://brainly.com/question/11293214

2. Relation between temperature and volume of an ideal gas: https://brainly.com/question/1403211

Answer details:

Grade: Senior school

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas, universal gas constant, pressure, volume, temperature, number of moles, 1.647 atm, 11 L, 0.703mol and 314K.

Answer 2

The pressure of the gas in atmospheres is 1.6 atm.

Using the ideal gas equation;

PV = nRT

Where;

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

From the values given in the question;

P = ?

n = 0.703 mol

V = 11.0 L

T = 314 K

R = 0.082 atm LK-1Mol-1

Substituting values and making P the subject of the formula;

P = nRT/V

P = 0.703 mol × 0.082 atm LK-1Mol-1 × 314 K/11.0 L

P = 1.6 atm

Learn more: https://brainly.com/question/18956703