Respuesta :
To solve this:Initial KE = 0 J meaning it begins at rest
ΔKE = ΔGPE meaning there is no friction
let speed at bottom of hill = v
so (1/2)mv² = mgΔh
v² = 2gΔh
v = √[2 * 9.8 * 22]
v = 21 m/s would be the answer if friction has no effect in slowing its motion
ΔKE = ΔGPE meaning there is no friction
let speed at bottom of hill = v
so (1/2)mv² = mgΔh
v² = 2gΔh
v = √[2 * 9.8 * 22]
v = 21 m/s would be the answer if friction has no effect in slowing its motion