We randomly select one card from 52, so there are 52 outcomes and:
[tex]\overline{\overline{\Omega}}=52[/tex]
We also know, that there are [tex]4\cdot3=12[/tex] face cards in a standard deck ([tex]\overline{\overline{F}}=12[/tex]) and only three of them are diamonds, so
[tex]\overline{\overline{D\cap F}}=3[/tex]
With this informations, we can calculate our probability:
[tex]P\left(D|F\right)=\dfrac{P\left(D\cap F\right)}{P(F)}=\dfrac{\frac{3}{52}}{\frac{12}{52}}=\dfrac{3\cdot52}{52\cdot12}=\dfrac{3}{12}=\boxed{\frac{1}{4}}[/tex]