Question

∆XYZ is a right triangle with right angle X, sin Y = m, and cos Y = k. What is cos Z - sin Z? Question 1 options: k - m 2m m - k k + m

Answer 1

Answer is m - k. You're welcome. 

Answer 2

sin Y= m

sin Y = m/1

So, hypotenuse is 1

Since sine is opposite over hypotenuse

So XZ= m and YZ = 1

Similarly, cos Y = k

cos Y = k/1

So adjacent side of angle Y is k

So XY = k

cos z - sin z = $\frac{XZ }{YZ } - \frac{XY}{YZ}$

cos z - sin z = $\frac{m }{1 } - \frac{k}{1}$

cos z - sin z = m - k

Option 3 is the answer