Question

A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity ofthe ball the instant before it hits the ground?

Answer 1

Answer: The velocity of the ball is 30.0 m/s

This can be calculated by using the value of acceleration as 10.0 m/s2 in free fall and the given time of 3.0 seconds. To get the velocity, one will have to multiply the acceleration with the given time and the quotient would result to 30.0 m/s. Mostly all object regardless of their mass, fall to earth with the same acceleration in the absence of air resistance and as the child drops the ball from a window, it gains speed as it falls.

Answer 2

The velocity of the ball the instant before it strikes the ground is 30m/s

Given the data in the question

• Since the ball was initial at rest before it was dropped by the child

• Initial velocity; $u = 0m/s$

• Time taken for the ball to hit the ground; $t = 3.0s$

• Final Velocity; $v = \ ?$

To find the velocity of the ball the instant before it hits the ground

We use the First Equation of Motion:

$v = u + at$

Where v is the final velocity, u is the initial velocity, t is time and a is the acceleration.

Now, since the ball was thrown from a particular height (window), it is under gravity and acceleration due to gravity; $g = 9.8m/s^2$

Hence, the equation becomes; $v = u + gt$

We substitute our values into the equation

$v = 0m/s + ( 10m/s^2\ *\ 3s )\\\\v = 0m/s + 30m/s\\\\v = 30m/s$

Therefore, the velocity of the ball the instant before it strikes the ground is 30m/s.

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