A box contains 6 red balls and 5 green balls. three balls are selected at random from this box "with replacement". what is the probability that exctly two of the three balls are green?

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19-03-2018
Mathematics

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A box contains 6 red balls and 5 green balls. three balls are selected at random from this box "with replacement". what is the probability that exctly two of the three balls are green?

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Аноним Аноним · Answer 1 · 2018-03-19T12:42:03+01:00

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Given information
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Red balls = 6
Green balls = 5

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Find total
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Total balls = 6 + 5
Total balls = 11

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Find probability
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G = green
R = red
P (R+ G + G) = 6/11 x 5/11 x 5/11 = 150/1331
P (G +R + G) = 5/11 x 6/11 x 5/11 = 150 /1331
P (G +G + R) = 5/11 x 5/11 x 6/11 = 150 /1331
Total probability = 150/1331 + 150 /1331 + 150 /1331 = 450/1331

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Ans: The probability is 450/1331
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