Question

What is the empirical formula of a compound that is 66.6% c, 11.2% h, and 22.2% o by mass?

Answer 1

The empirical formula of a compound is the simplest ratio of components making up the compound.
In 100 g of compound,there's 66.6 g of C, 11.2 g of H and 22.2 g of O
lets calculate for 100 g of compound 
                              C                                 H                             O
mass                     66.6 g                         11.2 g                      22.2 g
number of moles   66.6/12 g/mol           11.2/1 g/mol              22.2/ 16 g/mol
                               = 5.55 mol                =11.2 mol                 =1.3875 mol
 divide by the least number of moles 
                               5.55/1.3875              11.2/1.3875             1.3875/1.3875
                               = 4                             = 8.08                     = 1
round them off to the nearest whole number 
C - 4
H - 8
O - 1
Therefore empirical formula of compound is C₄H₈O

Answer 2

The empirical formula is the depiction of the number of atoms of chemical compounds or molecules in a reaction. The empirical formula of the compound is $\rm C_{4}H_{8}O$.

What is the empirical formula?

The depiction and the illustration of the atomic whole numbers in the compound are called empirical formulas. They show the ratios rather than the total number of atoms in the reaction.

In the 100 gm of the compound weight of carbon is 66.6 gm, hydrogen is 11.2 gm and oxygen is 22.2 gms.

Calculate the number of moles of Carbon:

$\begin{aligned} \rm Moles &= \dfrac{\rm Mass}{\rm Molar\; mass}\\\\&= \dfrac{66.6}{12}\\\\&= 5.55\;\rm moles\end{aligned}$

Calculate the number of moles of hydrogen:

$\begin{aligned} \rm Moles &= \dfrac{\rm Mass}{\rm Molar\; mass}\\\\&= \dfrac{11.2}{1}\\\\&= 11.2\;\rm moles\end{aligned}$

Calculate the number of moles of oxygen:

$\begin{aligned} \rm Moles &= \dfrac{\rm Mass}{\rm Molar\; mass}\\\\&= \dfrac{22.2}{16}\\\\&= 1.38\;\rm moles\end{aligned}$

Dividing the individual moles with the least number of moles, Carbon: Hydrogen: Oxygen = 4: 8: 1

Therefore, the empirical formula is $\rm C_{4}H_{8}O$.

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