Respuesta :

EQUILIBRUIM OF HCO2039 188CLOKB

HC₂H₃O₂ , equilibrium can be represented as:

HC₂H₃O₂ + H₂O--------->CH₃COO⁻ + H₃O⁺

HC₂H₃O₂, that is acetic acid dissociate in water that is H₂O and formed acetate anion that is CH₃COO⁻ and hydronium ions that is H₃O⁺.

Its equiibrium constant can be represented as:

Ka=\frac{[CH_{3}COO^{-1}]\times [H_{3}O^{+1}]}{CH_{3}COOH}

While NaC₂H₃O₂ can be dissociate as:

NaC₂H₃O₂------>CH₃COO⁻ + Na⁺

Sodium acetate that is NaC₂H₃O₂, dissociates as forming acetate anion and sodium cation.