Respuesta :
Formula for Manganese(II) bromide - MnBr₂
Formula for lead(II) nitrate - Pb(NO₃)₂
a double displacement reaction takes place where the ions are exchanged to form new compounds. The positive ion of one compound forms new compounds with the negative ion of the other compound.
Balanced reaction is as follows
MnBr₂ (aq) + Pb(NO₃)₂ ---> Mn(NO₃)₂(aq) + PbBr₂(aq)
Formula for lead(II) nitrate - Pb(NO₃)₂
a double displacement reaction takes place where the ions are exchanged to form new compounds. The positive ion of one compound forms new compounds with the negative ion of the other compound.
Balanced reaction is as follows
MnBr₂ (aq) + Pb(NO₃)₂ ---> Mn(NO₃)₂(aq) + PbBr₂(aq)
Answer:
2 Br⁻(aq) + Pb²⁺(aq) → PbBr₂(s)
Explanation:
Let's consider the molecular equation when aqueous solutions of manganese(II) bromide and lead(II) nitrate are combined.
MnBr₂(aq) + Pb(NO₃)₂(aq) → Mn(NO₃)₂(aq) + PbBr₂(s)
The complete ionic equation includes all the ions and the species that do not dissociate in water.
Mn²⁺(aq) + 2 Br⁻(aq) + Pb²⁺(aq) + 2 NO₃⁻(aq) → Mn²⁺(aq) + 2 NO₃⁻(aq) + PbBr₂(s)
The net ionic equation includes the ions that participate in the reaction and the species that do not dissociate in water.
2 Br⁻(aq) + Pb²⁺(aq) → PbBr₂(s)