Respuesta :
Zn(no3)2 + NaCO3 ----> ZnCO3 + 2NaNO3
Zn^2+(aq) + 2 NO3^-(aq) + 2Na^+(aq) + CO3^2(aq)- ---> ZnCO3(s) + 2Na^+(aq) + 2NO3^-(aq)
we cancel the the spectator in both side in this case is Na^+ and NO3-
this yield
Zn^2+(aq) + CO^-2(aq) -----ZnCO3(s)
Zn^2+(aq) + 2 NO3^-(aq) + 2Na^+(aq) + CO3^2(aq)- ---> ZnCO3(s) + 2Na^+(aq) + 2NO3^-(aq)
we cancel the the spectator in both side in this case is Na^+ and NO3-
this yield
Zn^2+(aq) + CO^-2(aq) -----ZnCO3(s)
Answer: The net ionic equation is written below.
Explanation:
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of zinc nitrate and sodium carbonate is given as:
[tex]Zn(NO_3)_2(aq.)+Na_2CO_3(aq.)\rightarrow ZnCO_3(s)+2NaNO_3(aq.)[/tex]
Ionic form of the above equation follows:
[tex]Zn^{2+}(aq.)+2NO_3^-(aq.)+2Na^+(aq.)+CO_3^{2-}(aq.)\rightarrow ZnCO_3(s)+2Na^+(aq.)+2NO_3^-(aq.)[/tex]
As, sodium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
[tex]Zn^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow ZnCO_3(s)[/tex]
Hence, the net ionic equation is written above.