Question

Three dice are going to be rolled. What is the probability that the first die rolled is a 1, the second die rolled is a 2, and the third die rolled is a 3? (If necessary, round to the nearest tenth)

Answer 1

Answer: The probability is 0.46%.

The chance of each given event happening is 1/6 because there are 6 different number on the dice and only 1 number is chose.

Therefore to find the combined probability, we have to multiply all the individual probabilities.

(1/6) x (1/6) x (1/6)

Or

(1/6)^3

The answer is about 0.46%,

Answer 2

Probability of getting first die rolled is a 1, second die rolled is a 2 and third die rolled is a 3 is equals to 0.46% (nearest tenth).

What is probability?

" Probability is a mathematical expression which represents the ratio of number of favourable outcomes to the total number of outcomes."

Formula used

Probability = $\frac{Number of favourable outcomes}{Total number of outcomes}$

According to the question,

Possible outcomes on each die = { 1, 2, 3, 4, 5, 6}

Substitute the value in the formula as per the given condition we get,

Probability that the first die rolled is a 1 =  ( 1 / 6)

Probability that the second die rolled is a 2 =  ( 1 / 6)

Probability that the third die rolled is a 3 =  ( 1 / 6)

Required Probability = (1 / 6) × (1 / 6) ×(1 / 6)

                                  =  ( 1 / 216)

                                  = 0.0046

                                  = 0.46% (nearest tenth)

Hence, required probability  (nearest tenth) = 0.46%

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