Respuesta :
Q1)
Ethanol is an alcohol that undergoes combustion in the presence of O₂ in air. Combustion yields water and carbon dioxide.
we are asked to write a balanced thermochemical equation, where the sum of the masses of products needs to be equal to the sum of the masses of the reactants.
when heat is released in the reaction, its known as an exothermic reaction and written with a negative sign. If heat is absorbed in the reaction, its called an endothermic reaction and written with a positive sign.
Combustion of ethanol is exothermic.
the balanced thermo chemical reaction for combustion of ethanol is as follows
C₂H₅OH(l) + 3O₂(g) ---> 2CO₂(g) + 3H₂O(l) ΔH = -1235 kJ/mol
Q2)
Stoichiometry of C₂H₅OH to CO₂ is 1:2
When 1 mol of ethanol reacts, then 2 mol of CO₂ is produced , during this reaction 1235 kJ is released
1 mol of CO₂ has 6.022 x 10²³ CO₂ molecules
Therefore 2 mol of CO₂ - 6.022 x 10²³ CO₂ molecules
When 6.022 x 10²³ CO₂ molecules are produced - 1235 kJ released
When 5.25×10²⁴ CO₂ molecules are produced - 1235 x 5.25×10²⁴ / (6.022 x 10²³) = 10 766.8 kJ of heat is released
Q3)
Energy of 1235 kJ is released when 1 mol of ethanol reacts
For 7525 kJ of energy to be released - 1 x 7525 /1235 mol = 6.09 mol of ethanol is required
stoichiometry of C₂H₅OH to O₂ is 1:3
1 mol of C₂H₅OH reacts with 3 mol of O₂
amount of O₂ moles that react with 6.09 mol of C₂H₅OH - 6.09 x 3 = 18.28 mol
Mass of O₂ reacted - 18.28 mol x 32 g/mol = 585.0 g
Ethanol is an alcohol that undergoes combustion in the presence of O₂ in air. Combustion yields water and carbon dioxide.
we are asked to write a balanced thermochemical equation, where the sum of the masses of products needs to be equal to the sum of the masses of the reactants.
when heat is released in the reaction, its known as an exothermic reaction and written with a negative sign. If heat is absorbed in the reaction, its called an endothermic reaction and written with a positive sign.
Combustion of ethanol is exothermic.
the balanced thermo chemical reaction for combustion of ethanol is as follows
C₂H₅OH(l) + 3O₂(g) ---> 2CO₂(g) + 3H₂O(l) ΔH = -1235 kJ/mol
Q2)
Stoichiometry of C₂H₅OH to CO₂ is 1:2
When 1 mol of ethanol reacts, then 2 mol of CO₂ is produced , during this reaction 1235 kJ is released
1 mol of CO₂ has 6.022 x 10²³ CO₂ molecules
Therefore 2 mol of CO₂ - 6.022 x 10²³ CO₂ molecules
When 6.022 x 10²³ CO₂ molecules are produced - 1235 kJ released
When 5.25×10²⁴ CO₂ molecules are produced - 1235 x 5.25×10²⁴ / (6.022 x 10²³) = 10 766.8 kJ of heat is released
Q3)
Energy of 1235 kJ is released when 1 mol of ethanol reacts
For 7525 kJ of energy to be released - 1 x 7525 /1235 mol = 6.09 mol of ethanol is required
stoichiometry of C₂H₅OH to O₂ is 1:3
1 mol of C₂H₅OH reacts with 3 mol of O₂
amount of O₂ moles that react with 6.09 mol of C₂H₅OH - 6.09 x 3 = 18.28 mol
Mass of O₂ reacted - 18.28 mol x 32 g/mol = 585.0 g
