Respuesta :
9 digits for 1-9
180 digits for 10-99
2700 digits for 100-999
451*4 = 1804 digits for 1000-1450
a total of 4693 digits
180 digits for 10-99
2700 digits for 100-999
451*4 = 1804 digits for 1000-1450
a total of 4693 digits
Answer:
The total number of digits required in numbering the pages of a book, which has 1,450 pages is 4693.
Step-by-step explanation:
The Total number of pages in the book is 1,450 pages.
Divide the amount 1450 into one-digit numbers, two-digit numbers, three-digit numbers, and four digits numbers.
Therefore,
One-digit numbers will be 1,2,3,4......9.
Count=9.
Two-digit numbers will be 10,11,12,13.......99.
Count=90.
Three-digit numbers will be 100,101,102,..............999.
Count=900.
Four-digit numbers will be 1000,1001,1002.......1450.
Count=451.
The Total number of words in printing the one-digit numbers is 9.
The Total number of words in printing the two-digit numbers is 90 multiply by 2 which is 180.
The Total number of words in printing the three-digit numbers is 900 multiply by 3 which is 2700.
The Total number of words in printing the four-digit numbers is 451 multiply by 4 which is 1804.
The total number of digits required in numbering the pages of a book, which has 1,450 pages will be the addition of words used in printing the one, two, three, and four digits numbers.
Therefore,
[tex]\rm{Printing\;words}=9+180+2700+1804\\\rm{Printing\;words}=4693.[/tex]
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